Turn around and you're two, turn around and you're four, turn around, and the Wright Challenge is stepping out of the door. Unfortunately, this is in fact the last problem of this season';s Wright Challenge puzzle contest! Every fortnight, the mysterious Doctor E supplied another puzzle for you to think about, and at the end of the semester, prizes of $60, $40 and $20 go to the top three finishers, with handsome certificates, suitable for framing, going to all sufficiently high-scoring finishers. Eligible contestants include University of Northern Iowa students, Iowa high school students, and Illinois high school students!

Turning in the correct solution to this week's puzzle by December 12th will earn 2 puzzle points. A correct solution along with the name of a University whose first building was originally home to Civil War orphans will get 3 puzzle points!

A continuous function is a function whose graph has no breaks in it.

One nice things about continuous functions is they have the intermediate value property: if (a 1,b 1) is on the graph and (a 2, b 2) is on the graph, then for every y-value b 3 between b 1 and b 2 there is an x value a 3 between a 1 and a 2 such that f(a 3) = b 3.

Anyway, let f be a continuous function with the following amazing property:

(a) Find f(793)

(b) Justify your answer.

The deadline for sending in solutions has expired. But feel free to take some time to work on this one, and click here to see the answer. Alternatively, click here to see the current challenge.

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